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lbaeza
7 Posts |
 Posted - 10/03/2006 : 16:30:02
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Hi
Last night I used my Dual Power Eprom Programmer to program a PIC:
This was my first shot. I never programmed a PIC before, only Eproms.
Anyway, before I tried to program it, I read the PIC contents without problems.
Then I loaded the HEX file, and clicked on the Program Chip button, but all I got was a "Error writing program area":
What I did was to set up the switches as shown on the image, put the PIC in the "PIC" socket, and go.
Am I missing something?
Questions:
1.- I have some NMOS EPROMs programmed before I started platying with the PIC. Does the Vpp I used for those EPROMs affect to the PIC programming? What value should I use for PIC programming?
2.- I have a "data-switch" between my programmer and my PC parallel port. Does this affect to the PIC programming? Should I avoid the "data-switch" and connect the programmer directly to the PC parallel port?
3.- Is the PIC (shown in the picture) placed at the right socket?
Help!
PS: Reading the PIC and 'blank-testing'-it run OK. Only the programming fails...No copy protection selected, the PIC was brand new... |
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| Reply #1
ZLM
2945 Posts |
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| Reply #2
lbaeza
7 Posts |
Posted - 10/20/2006 : 11:22:59
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OK
I downloaded ICProg, then went to the Hardware Setting menu (F3).
What programmer on the list should I select?
"WILLERPRO Programmer"?
Regards |
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| Reply #3
mcumall
78 Posts |
Posted - 10/20/2006 : 23:09:38
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Yes. You need select "Willerpro Programmer".
Also, if you are using Windows 2000 or WindowsXP, you need go to the Optons->Misc->Enable NT/2000/XP driver need checked.
I just see your first picture of programmer, the Vpp voltage setting is wrong. The right side of jumper need to short the lower 2 pins. Not the upper two pins. |
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| Reply #4
lbaeza
7 Posts |
Posted - 02/20/2007 : 15:30:17
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quote:
I just see your first picture of programmer, the Vpp voltage setting is wrong. The right side of jumper need to short the lower 2 pins. Not the upper two pins.
Hi
I updated the picture (please refresh), to show where the Vpp jumpers (JP5, JP6) are located.
If I short the lower 2 pins of JP6 ("the right side of the jumper"), given that the upper 2 pins of JP5 are connected, then I'll get 12.5 Vpp, according to the User Guide:
Is this correct?
BTW, I should have asked before: is 12.5 Vpp the right voltage for programming a 12C509A Microchip PIC?
Regards |
Edited by - lbaeza on 02/20/2007 15:32:28 |
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| Reply #5
lbaeza
7 Posts |
Posted - 04/23/2007 : 13:31:36
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Bump.
quote:
is 12.5 Vpp the right voltage for programming a 12C509A Microchip PIC?
Regards |
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| Reply #6
ZLM
2945 Posts |
Posted - 04/23/2007 : 22:14:01
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| Yes, 12.5 Vpp the right voltage. |
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| Reply #7
lbaeza
7 Posts |
Posted - 05/16/2007 : 08:50:51
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OK Thanks for your response.
So basically I fried my PIC using the wrong programming voltage...
Regards |
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PIC12C509A programming problem
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